Math, asked by asif5393, 10 months ago

Find the number of terms in the product of (3x^2+6xy+5y^2) and (3x+4y-13)

Answers

Answered by jedoeric2005
28

(3x² + 6xy + 5y²)(3x + 4y -13)

= 9x³+12x²y-39x²+18x²y+24xy²-78xy+15xy²+20y³-65xy

=9x³+20y³-39x²+39xy²-143xy+30x²y

Answered by shreyasachi21
15

Answer:

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