find the number of terms in the sequence -3,0,3_______54
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1
Answer:
6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51
Answered by
0
Answer:
Here
First term, a = - 3
Common difference = 3
Last term, an = 54
So using,
an = a + (n - 1)d
54 = - 3 + (n - 1)×3
57 = 3n - 3
3n = 60
n = 20
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