find the number of terms of an ap 54, 51, 48 so that their sum is 513
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a=54
d=51-54=-3
Sn=513
n/2×a+(n-1)d=513
n/2×54+(n-1)-3=513
n×54+(n-1)-3=513×2
n×54-3n+3=1026
54n-3n×n+3n=1026
-3n×n+57n=1026
now solve this equation by quadratic formula
d=51-54=-3
Sn=513
n/2×a+(n-1)d=513
n/2×54+(n-1)-3=513
n×54+(n-1)-3=513×2
n×54-3n+3=1026
54n-3n×n+3n=1026
-3n×n+57n=1026
now solve this equation by quadratic formula
Akash1511:
please complete it
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