Find the number of terms of the ap 4, 8, 12, 16, 472.
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Step-by-step explanation:
a - 4
d - 4
Sn = n/2[ 2a + (n-1)d ]
472 = n/2[2(4)+(n-1)(4)]
472= n/2[8+(n-1)(4)]
472= n/2[8-4+4n]
472= n/2×2[2+2n]
472=2n+2n²
0= 2n²+2n-472
= -b ± √b²+4ac/2a
here a=2,b=2,c=-472
substitute and you will get answer !!
you will get the n value and substitute
it in the forward formula ..
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