Math, asked by venkatragghav, 6 months ago

find the number of two-digit natural numbers divisible by 6

Answers

Answered by thatipallydivya88
1

Answer:

15

Step-by-step explanation:

the first two digit no. divisible by 6are12 and the last two nos. divisible by 6 is 97

so, let a=12,d=6,an=<97,them ,

an=a+(n-1)d

96=12+6n-6

96=n+1

n=15

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