find the number of two-digit natural numbers divisible by 6
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Answer:
15
Step-by-step explanation:
the first two digit no. divisible by 6are12 and the last two nos. divisible by 6 is 97
so, let a=12,d=6,an=<97,them ,
an=a+(n-1)d
96=12+6n-6
96=n+1
n=15
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