Find the number of unit cells in 117 gram of NaCl
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Given: mass of NaCl - m = 117g
To Find: number of unit cells in 117 grams of NaCl
Solution:
Concept and Formula used:
- NaCl Lattice exits in FCC arrangement.
- Hence 1 unit consists of 4 molecules of NaCl
- Molecular mass of NaCl = 23 + 35.5 = 58.5g
- Number of moles - n = Given mass(m)/molecular mass(M)
- Number of moles (n) = given number of molecules(N)/Avagadro number (Nₐ) Nₐ = 6.023 × 10²³
Applying the above formula to calculate the number of moles of NaCl:-
n = m/M
n = 117g/58.5g
n = 2 moles of NaCl
- 1 unit cell of NaCl has = 4 molecules of NaCl
- Calculate number of molecules in 2 moles of NaCl by using the given formula above:-
n = N/Nₐ
N = n × Nₐ
N = 2 × 6.023 × 10²³
N = 12.046 × 10²³
1 unit cell of NaCl has = 4 molecules of NaCl
number of unit cells with 12.046 × 10²³ molecules of NaCl
number of unit cells with 12.046 × 10²³ molecules of NaCl = 12.046 × 10²³/4
The Number of unit cells = 3.01 × 10²³
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