Question

The sum of four times the first number and three times the second number is 15. The difference of three times the first number and twice the second number is 7. Find the numbers

Answer 1

Answer:

Let the first number be x and second number be y

According to the question,

4x + 3y = 15 ••••••(i)

3x - 2y = 7 •••••••(ii)

Multiply equation (i) by 2 and equation (ii) by 3 we get,

8x + 6y = 30 •••••(iii)

9x - 6y = 21 •••••(iv)

Solving (iii) and (iv) we get,

17x = 51

x = 51/17

x = 3

Put the value of x in equation (i)

4(3) + 3y = 15

12 + 3y = 15

3y = 3

y = 1

Hence the first number is 3 and the second number is 1

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