Find the number of vertices of a polygon having 495 diagonals
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Answer:
Step-by-step explanation:
Answer:33 sides
Step-by-step explanation:
The number of diagonals of a polygon is equal to:
d=n(n-3)/2 where n is the number of sides.
So you would say:
495=n(n-3)/2
990=n(n-3)
0=n^2-3n-990
0=(n-33)(n+30)
n=33 or -30
But it cannot equal -30 because a polygon cannot have a negative quantity of sides. So the answer is 33 sides
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