find the number of way in which 5 people ABCDE can be seated at round table such that C and D must not sit together?
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Step-by-step explanation:
A,B,C,D,E
Number of circular arrangements of n circular objects =(n−1)!
Arrangement of 5 people =4! ways =24 ways
Let C,D be together always
⇒ C,D or D,C ⟶ 2! Ways
Arrangements of 4 units =3!×2 Ways =12 Ways
Total arrangements such that CandD are not together
=24−12 =12 Ways
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