Q2. Find the value of ‘a1’ so that the sum of the zeroes of the polynomial x2 + (2a1) x – a1 – 2 is equal to the product of its zeroes.
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Given : Sum of zeroes of the polynomial x² + (2a₁) x – a₁ – 2 is equal to the product of its zeroes.
To Find : Values of a₁
Solution:
polynomial x² + (2a₁) x – a₁ – 2
Sum of zeroes = -2a₁ / 1
Product of Zeroes = (-a₁ – 2 )/1
Sum of zeroes = Product of Zeroes
=> (-a₁ – 2 )/1 = -2a₁ / 1
=> -a₁ – 2 = -2a₁
=> a₁ = 2
x² + (2a₁) x – a₁ – 2
=> x² + 4x - 4
Sum of zeroes = product of zeroes = - 4
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