Math, asked by saisumana9966, 2 months ago

find the number of zeroes of q(y)=y^2- 1

Answers

Answered by vnmvs1205

0

Step-by-step explanation:

q(y) = y²-1.

Since q(y) is a second degree polynomial it will have 2 zeroes.

q(y) = y²-1 = y² - 1²

= (y+1)(y-1)

Therefore the zeroes of the polynomial are.

y + 1 = 0 and y - 1 = 0.

y = -1 and y = 1.

Hope it is helpful for you

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