Question

find the number of zeroes of x square _1​

Answer 1

Answer:

Step-by-step explanation:

x²+1=0

x²=-1

x=√-1

x=i ∉R

(or)

x=-b± √b²-4ac/2a

here

a=1

b=0

c=1

x=0 ± √0-4/2(1)

=0±√-4/2

=±2i/2

= +i or -i

i belongs to complex numbers.so x²+1 has no real zeroes

Answer 2

Answer:

Step-by-step explanation:

x^2 - 1 = (x - 1)(x + 1)

the zeroes of x^2 - 1 are - 1 and 1.