find the number such that if 25, 7 and 1 are added to it the product of the first and third result is equal to the square of the second
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let the number be x, y and z
so when the numbers are added
New numbers from are x+25,y+7 and z+1
(x+25)(z+1)=(y+1)²
so when the numbers are added
New numbers from are x+25,y+7 and z+1
(x+25)(z+1)=(y+1)²
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