Question

Find the number when divided by 41,42 &43 gives the remainder 1,3 & 5 respecively.​

Answer 1

Answer:

Let N be the smallest number.

This is a question of multiple divisors with multiple remainders.

Although the remainders seem different, but they are the same when we take their negative counterparts.

R[N20]=14 or (−6)

R[N25]=19 or (−6)

R[N35]=29 or (−6)

R[N40]=34 or (−6)

So, we can see N leaves the same remainder (-6) when divided by 20, 25, 35 or 40.

So, N=LCM(20,25,35,40)+(−6)

Or, N=1394 (Answer)

Step-by-step explanation:

this answer of different question but this pattern is like the question