Question

find the number which bears the same ratio to 7/33 that 8/21 does to 4/9

Answer 1

Hello,
we have that, the ratio of 8/21 to 4/9 is:
$\frac{8}{21}: \frac{4}{9} = \frac{8}{21} \times \frac{9}{4}= \frac{6}{7}$;

let the requidered number be n.
we have that the ratio of n to 7/33 to be:
$\frac{n}{ \frac{7}{33} }= \frac{6}{7}$

then
$\frac{33}{7}n= \frac{6}{7}$;
$33n=6$;
$n= \frac{6}{33} = \frac{2}{11}$


The number is $\frac{2}{11}$

bye :-)

Answer 2

Answer:

The required number is :

$x=\frac{2}{11}$

Step-by-step explanation:

Let the required number be x

First find the ratio of 8/21 to 4/9

$implies\text{Ratio = }\frac{8}{21}:\frac{4}{9}\\\\\implies Ratio = \frac{\frac{8}{21}}{\frac{4}{9}}\\\\\implies Ratio =\frac{8}{21}\times \frac{9}{4}\\\\\implies Ratio=\frac{6}{7}$

Now, given x bears the same ratio to 7/33

$\implies x :\frac{7}{33}=\frac{6}{7}\\\\\implies x = \frac{6}{7}\times\frac{7}{33}\\\\\implies x = \frac{6}{33}\\\\\implies x = \frac{2}{11}$

Therefore, The required number is :

$x=\frac{2}{11}$