Question

find the number which bears the same ratio to 7/33 that 8/21 does to 4/9.

Answer 1

Answer:

Number =  $\frac{2}{11}$

Step-by-step explanation:

Let say x is the number which bears the same ratio to 7/33 that 8/21 does to 4/9

x : 7/33  ::  8/21 : 4/9

=> $\frac{x}{\frac{7}{33}} = \frac{\frac{8}{21}}{\frac{4}{9}}$

=> $x\times {\frac{33}{7}} = \frac{8}{21}\times{\frac{9}{4}}$

=> $x\times {\frac{33}{7}} = \frac{2}{21}\times9$

=> $x\times {\frac{33}{7}} = \frac{2}{7}\times3$

=> $x\times {\frac{33}{7}} = \frac{6}{7}$

Cancelling 7 from both sides

=> $x\times33 = 6$

=> $x = \frac{6}{33}$

=> $x = \frac{2}{11}$

Number =  $\frac{2}{11}$