Find the number which divided 167 and 95 leaving 5 as remainder
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Answer:18
Stepby-step explanation:
First: If any number which is dividing both of them leaves remainder then ,in these type of question subtract it from the nmbers given, like in this question 167 and 95 are given leavingreainder 5 respectively.
167-5=162
95-5=90
By Euclid's division algorithm it's can be done or simply the HCF of both numbers can be taken.
162>90
162=90×1+72
r(remainder) not equals to 0
90=72×1+18
r not equals to 0
72=18×4+0
r=0
18 is the HCF of 162 and 90
18 is the number which when divides 167 and 95 leaves remainder 5.
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