Question

Find the number which divides 204 and 434 leaving remainder 5 in each case​

Answer 1

Answer:

the number is fifty four

Answer 2

Answer:

Given that the numbers 203 and 434 leaving remainder 5 in each case respectively. The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429 Prime factorization of 198=2^ * 3^ * 3^ * 11 Prime factorization of 129=3^ * 11^ * 13; HCF(198,429)=3^ * 11; =33 Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33

Step-by-step explanation:

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