find the number which when added to each term of ratio 27 : 35, changes the ratio to 4 : 5.
Answers
Answered by
50
Let the number be ( k ),
According to the question :
=> 5( 27 + k ) = 4( 35 + k )
=> 135 + 5k = 140 + 4k
=> 5k - 4k = 140 - 135
=> k = 5
Required number is 5
According to the question :
=> 5( 27 + k ) = 4( 35 + k )
=> 135 + 5k = 140 + 4k
=> 5k - 4k = 140 - 135
=> k = 5
Required number is 5
Answered by
37
Hey there !
Solution :
Let the number to be added be denoted by ' x '
So according to the question we get,
27 + x / 35 + x = 4 / 5
We need to find the value of x in the question. So cross multiplying we get,
=> 5 ( 27 + x ) = 4 ( 35 + x )
=> 135 + 5x = 140 + 4x
=> 5x - 4x = 140 - 135
=> x = 5
Hence the number to be added is 5.
Hope my answer helped !
shivshankar66:
you are right 5 is to be added.
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