find the number whose double is greater than its half by 45
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Let the reqd number be x.
Double of the number=2x
Half of the number=x/2
A/Q
Double of the number = half of the number+45
ie, 2x = x/2+45
ie, 3x/2 = 45
ie, x = 30
Double of the number=2x
Half of the number=x/2
A/Q
Double of the number = half of the number+45
ie, 2x = x/2+45
ie, 3x/2 = 45
ie, x = 30
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