Question

find the number whose fifth part increased by 5 is equal to its fourth part diminished by 5

Answer 1

x/5+5=x/4-5
x/5-x/4=-10
(4x-5x)/20=-10
-x=-200
x=200

Answer 2

Hey

Here is your answer,

the number whose fifth part increased by 5 means
1/5*x+5 ...................................(1)
Its forth part diminished by 5 means
1/4*x-5 ...................................(2)
now,let us equalise eq.(1) & eq.(2),we have

1/5*x+5=1/4*x-5
x/5+5=x/4-5
x+25/5=x-20/4
4(x+25)=5(x-20)
4x+100=5x-100
4x-5x= -100 - 100
- x = - 200
multiplying both sides by negative sign,we have
x=200
Hope it helps you!