Question

if one of the zeros of the polynomial 6xsquare2 - mx +35 is 5/3, find the value of m

Answer 1

If the question is this
$6 {x}^{2} - mx + 35$
Then x = 5/3
$6( { \frac{5}{3} })^{2} - m( \frac{5}{3} ) + 35 = 0$
$\frac{6 \times 25}{9} - \frac{5m}{3} + 35 = 0$
$\frac{50}{3} - \frac{5m}{3} + 35 = 0$
50 - 5m + 105 = 0
155 = 5m
m = 31
This is the value of my that is 31