Find the number whose sum of digits is 6 and if we add 18 to it the digits will become reverse?
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Answered by
9
Hey mate here is your answer::::
Let the digit at one's place be X
Let the digit at ten's place be 6-X
No formed= X+10(6-x)
=X+60-10x
=-9x+60
No formed on reversing the digits and adding 18 will be :::::
10(X)+6-x
10x+6-x
9x+6
Now,,
-9x+60=9x+6-18
-9x+60=9x-12
-9x-9x=-12-60
-18x=-72
X=-72/-18
X=4
So , the original number will be
-9x+60
-9(4)+60
-36+60
24
So your answer comes out to be {24}
Let the digit at one's place be X
Let the digit at ten's place be 6-X
No formed= X+10(6-x)
=X+60-10x
=-9x+60
No formed on reversing the digits and adding 18 will be :::::
10(X)+6-x
10x+6-x
9x+6
Now,,
-9x+60=9x+6-18
-9x+60=9x-12
-9x-9x=-12-60
-18x=-72
X=-72/-18
X=4
So , the original number will be
-9x+60
-9(4)+60
-36+60
24
So your answer comes out to be {24}
Answered by
4
your answer is 24 hope u may not get lot of explanain
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