Find the Numbers of x
How many numbers x (x being Integer) with 10 < = x < = 99 are 18 more than the sum of their digits?
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Let the integer at ten's place be x'' and at unit's place be 'y'.
Therefore, num = 10x + y
According to the condition:-
10x + y = 18 + x + y
10x -x + y - y = 18
9x = 18
x = 2
Now with ten's place as 2, there can be 10 possible values of y from 0 to 9.
Total number of num = 10 Answer.
Therefore, num = 10x + y
According to the condition:-
10x + y = 18 + x + y
10x -x + y - y = 18
9x = 18
x = 2
Now with ten's place as 2, there can be 10 possible values of y from 0 to 9.
Total number of num = 10 Answer.
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