Question

Find the numbers such that one is 3/2 times the other, and the sum is 20.​

Answer 1

Answer:

8 & 12

Step-by-step explanation:

Let the Smaller Number be x.

Then, Other Number = $\frac{3x}{2}$

$\frac{3x}{2}$ + x = 20

3x + 2x = 40 (Multiplied throughout by 2)

5x = 40

x = 40/5 = 8

Numbers are: x = 8

$\frac{3x}{2}$ = (3 x 8)2 = 24/2 = 12

Answer 2

Given :-

The two numbers such that one is 3/2 times the other.

Their sum is 20.

To find :-

The two numbers

Solution :-

Let the other number be X

Then the number = 3/2 times the other

= (3/2)×X

= 3X/2

Given that

Their sum = 20

=> (3X/2 )+X = 20

=> (3X+2X)/2= 20

=> 5X/2 = 20

=> 5X = 20×2

=> 5X = 40

=> X = 40/5

=> X = 8

The other number = 8

The number = (3/2)×8

= (3×8)/2

= 3×4

= 12

Answer :-

The two numbers are 8 and 12

Check :-

The two numbers = 8 and 12

Their sum = 8+12 = 20

3/2 of 8 = (3×8)/2 = 24/2 = 12

Verified the given relations in the given problem.