Question

Find the numbers which are in the ratio 2:3:5 and sum of
their squares is 10982.

Answer 1

Answer:

let the numbers be = 2x , 3x , 5x

Given sum of squares = 10982

• (2x) ² + (3x)² + ( 5x) ²= 10982
• 4x² + 9x² + 25x² = 10982
• 38x² = 10982
• x² = 10982/ 38
• x² = 289
• x = 17

First number = 2* 17= 34

Second number = 3 * 17 = 51

Third Number = 5 * 17 = 85

Answer 2

Answer:

First number = 2* 17= 34

Second number = 3 * 17 = 51

Third Number = 5 * 17 = 85

Step-by-step explanation:

let the numbers be = 2x , 3x , 5x

Given sum of squares = 10982

(2x) ² + (3x)² + ( 5x) ²= 10982

4x² + 9x² + 25x² = 10982

38x² = 10982

x² = 10982/ 38

x² = 289

x = 17