Question

find the numerical value of nuclear density for a nucleus of mass number A?

Answer 1

Answer:

Density of nuclei is given as

$\rho = 2.3 \times 10^{17} kg/m^3$

Explanation:

As we know that mass number is A

let say the atomic number is z

so number of protons in it is z and number of neutrons in it is A - z

so total mass of the nuclei is given as

$M = zm + (A - z)m$

$M = Am$

now we know that radius of nuclei is given as

$r = r_o(A^{1/3})$

where we know that

$r_o = 1.2 \times 10^{-15} m$

now we have

$\rho = \frac{Am}{\frac{4}{3}\pi r_o^3 A}$

$\rho = \frac{3m}{4\pi r_o^3}$

now we have

$m = 1.66\times 10^{-27} kg$

$\rho = 2.3 \times 10^{17} kg/m^3$

#Learn

Topic : Nuclei density

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