Chemistry, asked by sumayya14, 11 months ago

the amount of NA2CO3 present in 100 ml of 0.1 M NA2CO3 is

Answers

Answered by justsri1972

2

Vml = 100ml

M =0.1

GMW = 106

w=?

formula of molarity

M=w/GMW. × 1000/Vml

0.1= w/106. × 1000/100

0.1=5w/53

w=53/50

I hope it will help you

Answered by kumarinimita2003

5

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