Question

find the odd multiples of 3 between 100 and 999
(Correct ans i will mark u as brainliest any other i will report
plseee i beg u to give the correct answer)​

Answer 1

Answer:

Before answering this u have to understand that all numbers divisible by 2 and 3 are divisible by 6.

Step-by-step explanation:

For this type of problems, follow this simple formula!! If you want to know to the number of multiples of a number lets say “n”, from a number “a” to “b”, then the number of divisors is given by [ (b−a)/(b−a)/ n], where [.] Represents the greater integer. If you don't know what greatest integer means, then read this:-

For a given value x, [x] means the greatest integer less than or equal to x, when [.] represents the greatest integer function.

Let's see the following example:-

[3.4]=3,

[5.9]=5,

[23.1]=23,

[2.7]=2,

(Where [x] represents the greatest integer)

I hope you understood what a greatest integer function is.

Now let's come to your question.

Since it is mentioned BETWEEN 100 and 999, the numbers under consideration are,

a=101, b=998, n= 6

So now let is apply the formula.

Number of multiples = [ (b−a)/n](b−a)/n] =[ (998−101)/6]=[897/6]=[149.5]=149.(998−101)/6]=[897/6]=[149.5]=149.

Therefore the number of multiples of 6 between 100 and 999 is 149.

The given formula can be applied in all such type of questions and is not limited to this question only!! Therefore all questions of this kind can be solved without much confusion!

Hope it helped!