find the % of chromium in ammonium chromate
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Ammonium dichromate = (NH₄)₂Cr₂O₇
MOLECULAR MASS =
(14 + 4 )2 + 52×2 + 16×7
= 36 + 104 + 112
= 252 u
Percentage of oxygen :- 112/252 × 100= 44.4 %
Percentage of chromium:- 104/252 × 100 = 41.2 %
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