find the % of each element in CaSO4.1/2H2O.
molecular mass
Ca: 40
S: 32
O: 16
H: 1
plz tell I will mark as Branliest
plz anyone.....
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Answer:
Molecular mass of calcium hydroxide = 40+32+4*16+1/2(2*1+16)
= 72+64+1/2(18)
= 136+9
= 145
% composition of Ca = (40*1/145)*100
= 27.58 %
% composition of S = (32*1/145)*100
= 22.06 %
% composition of O = {(4*16+16/2)/145}*100
= (72/145)*100 = 49.65 %
% composition of H = (1*1/145)*100
= 0.70 %
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