Question

find the of the circle having (2,3) and (4,0) as the end point of a diameter​

Answer 1

Step-by-step explanation:

we should use Distance formula ;

$\sqrt{(x2 - x1) {}^{2} + {(y2 - y1) }^{2} }$

so, x1 = 2

x2= 4

y1= 3

y2= 0

=>

$\sqrt{(4 - 2) {}^{2} + (0 - 3) {}^{2} }$

=>

$\sqrt{(2) {}^{2} + (- 3) {}^{2} }$

=>

$\sqrt{4 + 9}$

=>

$\sqrt{13}$

so the distance is$\sqrt{13}$