Question

find the output of the following:
x = 10;
y = ++x + x++ * x++

Answer 1

Answer:

int x=10,y=0;

y= ++x+x++*x++

=11+11*12

=11+132

=143

How it executed:

variable x is declared and initialized with value 10 and y is initialised

y=++x + x++*x++

In Java compiler it will divide the problem in two parts

y=++x+(x++*x++)

Step 1:x becomes 11 due to pre increment and the value is incremented to x as 11 so final value becomes 11

y=11+(x++*x++)

Step 2:final value of x is 11 so the value is incremented but the incremented value is not assigned due to post increment hence x remains 11 but the final value of x becomes 12

y=11+(11*x++)

Step 3:final value of x is now 12 so this time also due to post increment the assigned value remains the same

Hence,

y=11+(11*12)

=11+132

=143