Question

find the oxidation no of H3P2O-7 in P​

Answer 1

Answer:

Explanation:

Given :

Compound H₃P₂O₇⁻

We are asked to find O.N. of P :

We know :

O.N. of H = + 1

O.N. of O = - 2

Net charge on compound is - 1 .

Let O.N. of P be x .

( 1 × 3 ) + ( 2 × x ) + ( 7 × ( - 2 ) ) = - 1

3 + 2 x - 14 = - 1

2 x - 11 = - 1

2 x = + 10

x = + 10 / 2

x = + 5

Therefore , O.N. of P in H₃P₂O₇⁻ is + 5