Question

Find the oxidation number of Cl in HCl, HClO, $ClO_{4}^{-1}$, and Ca(OCl)Cl.

Answer 1

HEY MATE,
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Let the oxidation number of Cl be x
then

1). in HCl

x + 1 = 0
x = - 1
oxy. no. of Cl is -1
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2). in HClO

1 + x + (-2) = 0
x = 1
oxy. no. of Cl is +1
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3). in $ClO_{4}^{-1}$

x + 4(-2) = -1
x = +7
oxy. no. of Cl is +7
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4). in Ca(OCl)Cl
( here Cl at the end have the oxidation (-1) same as HCl)

2 + (-2) + x + (-1) = 0
x = + 1
oxy. no. of Cl is +1

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