find the roots of √3x+10x-8√3=0
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Perhaps you have made a mistake...
For linear polynomial there is only one root but you have made it two..
I am solving it in two ways...one linear and in one quadratic...
Case 1:- When 1st term is linear ..i.e. x
f(x)=x(√3+10)=8√3
=x=(8√3)/(10+√3)
Case 2:- When 1st terms is quadratic..i.e.x^2
f(x)=√3x^2+10x+8√3
=√3x^2+6x+4x+8√3
=√3x(x+2√3)+4(x+2√3)
=(x+2√3)(√3x+4)
Hope it helps you....and you can understand...
For linear polynomial there is only one root but you have made it two..
I am solving it in two ways...one linear and in one quadratic...
Case 1:- When 1st term is linear ..i.e. x
f(x)=x(√3+10)=8√3
=x=(8√3)/(10+√3)
Case 2:- When 1st terms is quadratic..i.e.x^2
f(x)=√3x^2+10x+8√3
=√3x^2+6x+4x+8√3
=√3x(x+2√3)+4(x+2√3)
=(x+2√3)(√3x+4)
Hope it helps you....and you can understand...
Answered by
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hope this helps u...
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Yuvarajv952:
thx
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