Question

Find the oxidation number of cr in K2Cr2O7​

Answer 1

Answer:

Potassium exhibits an oxidation state of +1, oxygen exhibits an oxidation state of -2

So, the total charge of potassium ions is +1(2)=+2, while oxygen ions is −2(7)=−14.

Let x be the oxidation number of two chromiums.

Hence we can write the equation as

2+x−14=0

−12+x=0

x=12

So, two chromium atoms have an oxidation number of +12.

So one chromium atom will have an oxidation number of +12 /2=+6.

So oxidation number of Cr in K2Cr2O7 is +6.

Answer 2

Answer:-

Let x be the oxidation number of two chromiums.

So, two chromium atoms have an oxidation number of +12.

So one chromium atom will have an oxidation number of $\frac{ + 12}{2} = + 6$.

So oxidation number of Cr in K2Cr2O7 is +6.

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