Find the pair of natural numbers if its LCM is78 and HCF is 13
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Answered by
1
Let the numbers be x and y
Given that hcf and lcm is 13 and 78
x × y = 78 × 13
xy=1014
We have got the product of numbers
Now as we know that hcf is a number which is highest common factor and lcm is product of all factors that means that the numbers are divisible by 13 and they are less than 78
By guess
You get numbers as 26 and 39
Given that hcf and lcm is 13 and 78
x × y = 78 × 13
xy=1014
We have got the product of numbers
Now as we know that hcf is a number which is highest common factor and lcm is product of all factors that means that the numbers are divisible by 13 and they are less than 78
By guess
You get numbers as 26 and 39
CuriousDhruv:
Also 39 × 26= 1014, Mark me as brainliest
Answered by
1
If LCM=78and HCF=13
the no.78comes in the table of 13 in six times.
So,the LCM of 78 and 13 is 78.
And the no.13 is the common factor of 78 which is highest.
So,(78,13) is the pair of natural no. which LCM is 78 and HCF is 13.
the no.78comes in the table of 13 in six times.
So,the LCM of 78 and 13 is 78.
And the no.13 is the common factor of 78 which is highest.
So,(78,13) is the pair of natural no. which LCM is 78 and HCF is 13.
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