Question

Find the peirmeter of recangular field whose length is 4 times its width and which has area equal to 20736sq.meter

Answer 1

The answer is 720 meter

Answer 2

here's your answer looking for

let b= x
and
l= 4x
so,

area = l×b
$20736 = 4x \times x \\ \\ 20736 = 4 {x}^{2} \\ \\ {x }^{2} = 5184 \\ \\ x = \sqrt{5184} \\ \\ x = 72$
so ,

b= x= 72
and
l= 4x= 288

so,

perimeter = 2(l+b)

$= 2(288 + 72) \\ \\ = 2 \times 360 \\ \\ = 720 {m}^{2}$
hope you are satisfied with my answer