Question

find the perendicular distance of p(-5 , 2) from x -axis

Answer 1

Hi ,

Perpendicular distance from x - axis

= 2

i.e y - coordinate of the point

I hope this helps you.

:)

Answer 2

Heya user !!!

Here's the answer you are looking for

P ( -5, 2)

That means the point has x- coordinate -5.
And the y - coordinate on x axis is 0

⏩So the point P( -5, 2) will be perpendicular to ( -5, 0) on x axis.

⏩Since the y axis is perpendicular to x axis, the perpendicular distance of P( -5, 2) from x axis is equal to the y coordinate of the point, that is 2 units.

⏩It can also be done by the distance formula.

Using distance formula,

The distance of P( -5, 2) from x axis that is ( -5, 0) is

$\sqrt{ ({( - 5)}^{2} - {( - 5)}^{2}) + ({2}^{2} - {0}^{2}) } \\ = \sqrt{0 + {2}^{2} } \\ = \sqrt{4} \\ = 2$

So the distance is 2 units.

★★ HOPE THAT HELPS ☺️ ★★