find the perimeter and area of a rectangle whose breadth is 7 cm and diagonal is 25 CM
Answers
Answer:
perimeter of rectangle
B (breadth) =7 CM
D (diagonal)=25 CM
L (length) = ?
L = √d2 - W2
=√25 square - 7 square
=24 CM
P =2(l +w)
=2.(24 + 7) CM
=62 CM.....
Area of rectangle
A=WL
=7.24 CM
=168cm ........
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Answer:
Step-by-step explanation:
The diagonal of a right triangle is the hypotenuse and is designated as side c .The width of a right triangle is side b , and the height is side a
The Pythagorean equation is c2 = a2 + b2.
c = 25 cm
b = 7 cm
a = ?
Rearrange the equation to solve for side a.
a2 = c2 − b2
Substitute the known values into the equation.
a2 = ( 25 cm )2 − ( 7cm )2
a2 = 625 cm2 - 49 cm2
a2 = 576cm2
Take the square root of both sides.
√a2 = √576 cm2
a = 24 cm
Area = Length * breadth
= 24 * 7
= 168 cm²
Perimeter = 2 ( length + breadth )
= 2 ( 24 + 7 )
= 2 ( 31 )
= 62 cm
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