find the perimeter and area of a rectangle whose length is 1 m 25 cm and breadth is 80 CM
Answers
Answered by
22
hey user
Given length=1m,25cm=125cm
breadth=80cm
perimeter of rectangle =2(l+b)
=2(125+80)
perimeter=2(205)=410cm
Area of rectangle=l×b=125×80=10000cm^2
Hope it helps
Given length=1m,25cm=125cm
breadth=80cm
perimeter of rectangle =2(l+b)
=2(125+80)
perimeter=2(205)=410cm
Area of rectangle=l×b=125×80=10000cm^2
Hope it helps
Shivdasmourya:
area in square
Answered by
26
UILength of Rectangle = 1 m 25 cm
= 100 cm + 25 cm = 125 cm
Breadth = 80 cm
Area of rectangle = 125 × 80
= 10000 cm²
We know that
1000 cm ² = 1 m²
So 10000 cm ² = 10 m²
Thus Area of rectangle = 10 m²
The Perimeter = 2(l+b)
= 2( 125 + 80) cm
= 2 ( 205)
= 410 cm
= 4.1 m
Hope you like it please mark as brainliest.
= 100 cm + 25 cm = 125 cm
Breadth = 80 cm
Area of rectangle = 125 × 80
= 10000 cm²
We know that
1000 cm ² = 1 m²
So 10000 cm ² = 10 m²
Thus Area of rectangle = 10 m²
The Perimeter = 2(l+b)
= 2( 125 + 80) cm
= 2 ( 205)
= 410 cm
= 4.1 m
Hope you like it please mark as brainliest.
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