Question

Find the perimeter and area of rectangle in which l=13cm,b=12cm







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Answer 1

$\huge\mathfrak\blue{Solution:–}$

Question:-

✭ Find the perimeter and area of rectangle in which l=13cm,b=12cm.

Answer:-

✭Perimeter of the rectangle = 50 cm

✭Area of the rectangle = 156 cm²

Given:-

✭Length and breadth of rectangle is 13 cm and 12 cm respectively.

To calculate:-

✭Perimeter and area of the rectangle

Step by step explanation:-

✭Perimeter of the rectangle = 2(l+b)

= 2(13+12) cm

= (2×25) cm

= 50 cm

✭Area of the rectangle = (l×b)

= (13×12) cm²

= 156 cm²

$\huge\mathfrak\red{Extra\:Formulae:–}$

✭Perimeter of the rectangle = 2(l+b)

✭Area of the rectangle = (l×b)

✭Diagonal of rectangle = √l²+b²

$\huge\mathfrak\green{Extra\: Information:–}$

✭A rectangle is simple closed figure which have its opposite sides parallel and equal.

Properties of rectangle:-

✭ It's angles are 90°.

✭A rectangle have parallel and equal opposite sides.

✭It's digonals bisect each other into two equal parts.

✭It's diagonals bisects each other at 90°

Answer 2

Answer:

Perimeter= 2(l+b)

2(13+12)

2*25

50

Area= l*b

13*12

156

Hope it helps!