Question

Find the perimeter and area of rectangle with length 6.2cm and breadth 5.8cm

Answer 1

Answer:

Step-by-step explanation:perimeter=2(l+b)

=2(6.2+5.8)

=2*12=24cm

Area=l*b

=6.2*5.8=35.96cm^2

Answer 2

Given ,

$\star$Length = 6.2 cm

$\star$Breadth = 5.8 cm

We have to calculate the perimeter and area of the given rectangle , so

$\huge{ \star } \: \: \sf \large \pink{ \fbox{ \fbox{Perimeter = 2 \: (L + B) \: }}}$

$\sf= 2 \: (6.2 + 5.8) \\ \\ \sf = 2 \: (12) \\ \\ \sf = 24 \: \: cm$

$\huge{ \star } \: \: \pink{\large \fbox{ \fbox{ \sf \: Area = L × B \: }}}$

$\sf = 6.2 \times 5.8 \\ \\ \sf = \frac{62}{10} \times \frac{58}{10} \\ \\ \sf = \frac{3596}{100} \\ \\ \sf = 35.96 \: \: {cm}^{2}$

Therefore, perimeter of the rectangle is 24 cm & area of the rectangle is 35.96 cm²