Question

Find the perimeter and area of the quadrilateral ABCD in which AB= 42 cm, BC= 21 cm, CD= 29 cm, DA= 34 cm and angle CBD=90 degree

Answer 1

Answer:

Perimeter of quadrilateral ABCD is 126 cm and area of quadrilateral ABCD is 384 sq. cm.In ΔABC ,AC = 20 cm , AB = 21 cm and ∠CAB = 90°.Therefore , By Pythagoras TheoremBC² = AC² + AB²BC² = 20² + 21² = 400+441 = 841BC = 29 cmNow Perimeter of quadrilateral ABCD = AB + BC + CD + AD Perimeter = 21+29+42+34 = 126 cm.Now area of quadrilateral ABCD is equal to Area of ΔABC + Area of ΔCAD .Now area of ΔABC =  = 20 × 21 / 2 = 210 sq cm.Area of ΔCAD =    , Using Heron's formulaNow s = (a+b+c)/2 = (42+34+20)/2 = 48 sq cm.Now, area =  =  =  = 336 sq. cmNow area of quadrilateral ABCD = Area of ΔABC + Area of ΔCAD Area of quadrilateral ABCD = 48 + 336 = 384 sq cm.

Read more on Brainly.in - https://brainly.in/question/8528647#readmore

Step-by-step explanation: