Math, asked by afnanmalik72, 10 months ago

Find the perimeter and area of the square whose side is:
a) 3√2x
b) 3x + 8​

Answers

Answered by Tinuarjun
6

Step-by-step explanation:

area= side×side

perimeter= 4×side

a). area=(3√2x)(3√2x) = 18x²

perimeter=4 × 3√2x = 12√2x

b).area=(3x+8)(3x+8) =9x²+48x+64

perimeter= 4 × (3x+8) = 12x + 32

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