Question

find the perimeter of a rectangle in which the diagonal is 10 centimetre and its one side is 8 centimetre .​

Answer 1

Answer:

28cm

Step-by-step explanation:

Lenght=8cm (=l)

Diagonal=10cm (=b)

Breadth=? (lets take=x)

By Pytahgoras theorem

(diagonal)²=(lenght)²+(breadth)²

10²=8²+x²

x²=100-64

x²=36

x=6cm

So, perimeter=2(l+b)

                      =2(8+6)

                      =28cm

Answer 2

Step-by-step explanation:

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