Question

Find the perimeter of a rectangle of length 14cm and breadth 6.3cm.​

Answer 1

$\red{\bigstar \large\underline{\boxed{\bf\pink{Answer:-}}}}$

Diagram :-

$\begin{gathered} \pink{\begin{gathered} \sf{6.3 \:cm}\huge\boxed{ \begin{array}{cc} \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{14 \: cm} \end{gathered}}\end{gathered}$

$\large \tt\green{Given :-}$

• Length of Rectangle = 14 cm
• Breadth of rectangle = 6.3 cm

$\large \sf \orange{Solution:-}$

$\blue{ \underline{ \fbox{ \sf {Perimeter \tiny{ (Rectangle)}}}}}$

$\sf \green{ \mapsto \: 2(l + b)}$

$\sf \orange{ \mapsto \: 2(14 + 6.3) \: cm}$

$\sf \purple{ \mapsto2(20.3)}$

$\color{violet}{ \underline{ \boxed{ \sf {\mapsto \: 40.6 \: cm \: }}}}$

$\color{yellow}{ \underline{ \boxed{ \sf { \therefore \: The \: Perimeter \: of \: rectangle = 40.6 \: cm}}}}$

Answer 2

Answer:

$\large\sf{\pmb{\underline{\green{Given:-}}}}$

• ● Lenght of Rectangle = 14 cm
• ● Breadth of Rectangle = 6.3 cm

$\large\sf{\pmb{\underline{\green{To \: Find :-}}}}$

• ● Perimeter of Rectangle

$\large\sf{\pmb{\underline{\green{Using \: Formula:-}}}}$

$\bigstar\underline{\boxed{\sf{\pink{Perimeter \: of \: Rectangle = 2(Lenght + Breadth)}}}}$

$\large\sf{\pmb{\underline{\green{Solution:-}}}}$

$\begin{gathered} \\ \end{gathered}$

${\dashrightarrow{\sf{Perimeter \: of \: Rectangle = 2(Lenght + Breadth)}}}$

$\begin{gathered} \\ \end{gathered}$

• ● Substituting the values

$\begin{gathered} \\ \end{gathered}$

${\dashrightarrow{\sf{Perimeter \: of \: Rectangle = 2(14+ 6.3)}}}$

$\begin{gathered} \\ \end{gathered}$

${\dashrightarrow{\sf{Perimeter \: of \: Rectangle = 2(20.3)}}}$

$\begin{gathered} \\ \end{gathered}$

${\dashrightarrow{\sf{Perimeter \: of \: Rectangle = 2 \times 20.3}}}$

$\begin{gathered} \\ \end{gathered}$

${\dashrightarrow{\sf{Perimeter \: of \: Rectangle =40.6 \: cm}}}$

$\begin{gathered} \\ \end{gathered}$

$\bigstar\underline{\boxed{\sf{\pink{Perimeter \: of \: Rectangle =40.6 \: cm}}}}$

$\begin{gathered} \\ \end{gathered}$

$\large\sf{\pmb{\underline{\green{Diagram:-}}}}$

${\underline{\pmb{\frak{ \dag \: The \: diagram \: of \: Rectangle \: is \: given \: below :-}}}}$

$\star\sf{ \big(For \: App \: Users \big)}$

$\begin{gathered}\tiny\begin{gathered} {\begin{gathered} \sf{6.3 \:cm}\huge\boxed{ \begin{array}{cc} \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{14 \: cm} \end{gathered}}\end{gathered}\end{gathered}$

• ● Length = 14 cm
• ● Breadth = 6.3

$\star\sf{ \big(For \: Web \: Users \big)}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 14 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 6.3 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

• ● Request:- Please see the diagram from website Brainly.in...

$\begin{gathered} \\ \end{gathered}$

$\large\sf{\pmb{\underline{\green{Know \: More :-}}}}$

$\begin{gathered}\scriptsize\begin{gathered}\begin{gathered}\bigstar \: \bf\underline{More \: Useful \: Formulae } \: \bigstar  \\ \begin{gathered}{\boxed{\begin{array} {cccc}{\sf{{\leadsto TSA \: of \: cube \: = \: 6(side)^{2}}}} \\  \\{\sf{{\leadsto LSA \: of \: cube \:= \: 4(side)^{2}}}}  \\  \\{\sf{{\leadsto Volume \: of \: cube \: = \: (side)^{3}}}} \\  \\ {\sf{{\leadsto Diagonal \: of \: cube \: = \: \sqrt(l^{2} + b^{2} + h^{2}}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: cube \: = \: 4(l+b+h)}}} \\  \\ {\sf{{\leadsto CSA \: of \: sphere \: = \: 2 \pi r^{2}}}} \\  \\ {\sf{{\leadsto SA \: of \: sphere \: = \: 4 \pi r^{2}}}} \\ \\{\sf{{\leadsto TSA \: of \: sphere \: = \: 3 \pi r^{2}}}} \\  \\ {\sf{{\leadsto Diameter \: of \: circle \: = \: 2r}}} \\  \\ {\sf{{\leadsto Radius \: of \: circle \: = \: \dfrac{d}{2}}}} \\  \\ {\sf{{\leadsto Volume \: of \: sphere \: = \: \dfrac{4}{3} \pi r^{3}}}} \\  \\ {\sf{{\leadsto Area \: of \: rectangle \: = \: Length \times Breadth}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: rectangle \: = \:2(length+breadth)}}} \\  \\{\sf{{\leadsto Perimeter \: of \: square \: = \: 4 \times sides}}}\end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$