Physics, asked by ranirajak, 4 months ago

Find the perimeter of a rectangle of length 41 cm and breath 28 cm. What is the area of rectangle??​

Answers

Answered by AnnieStar
51

\huge{\underbrace{\textsf{\textbf{\color{lightpink}{Question:-}}}}}

Find the perimeter of a rectangle of length 41 cm and breath 28 cm. What is the area of rectangle??

\huge{\underbrace{\textsf{\textbf{\color{lightblue}{Answer:-}}}}}

\sf Given\begin{cases} &\sf{Length\;of\;the\; rectangle, \;l\;=\be{41\:cm}}\\&\sf{Breadth\;of\;the\;square,\;b\;=\bf{28\;cm}}\end{cases}\\ \\

\boxed{ \sf \blue{  To \: Find : }}

Area of the rectangle = ❓

Perimeter of the rectangle = ❓

\green{\underline\bold{Now,}}

\green{\underline\bold{We \:know,}}

\boxed{ \sf \blue{ Area\: of \:a \:rectangle \:= \:l\:×\:b.}}

= 41 × 28

= 1148 cm sq.

\green{\underline\bold{And,}}

\boxed{ \sf \blue{ Perimeter\: of \:a \:rectangle\:= \:2\:×\:(l\:+\:b)}}

= 2 (l + b)

= 2 (41 + 28)

= 138 cm

\pink{\underline\bold{∴\: Area \:of \:the\: rectangle \:= \: 1148\: cm \:sq..}}

\pink{\underline\bold{ Perimeter\: of\: the\: rectangle \:= \:138.}}

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Answered by AestheticSky
16

\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}

Given:-

  • length of the rectangle = 41 cm.
  • breadth of the rectangle = 28 cm

To find:-

  • Area of the rectangle

Formula to be used:-

\underline{\boxed{\sf Area = length × breadth }}

Solution:-

:\implies \sf Area = 41 × 28

:\implies \sf Area = 1148 cm²

hence, the required area is 1148 cm²

Additional information

Perimeter of the rectangle :-

\underline{\boxed{\sf perimeter = 2 ( length + breadth) }}

Area of square:-

\underline{\boxed{\sf area = side² }}

perimeter of square:-

\underline{\boxed{\sf perimeter = 4×sides}}

_________________________

\small\bf\pink{@itzsplendidcharm࿐}

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