find the perimeter of a rectangle whose adjacent sides are 5x²+2xy-13÷ 2x²-6xy+11
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Step-by-step explanation:
sides of rectangle
length= 5x²+2xy-13
breadth=2x²-6xy+11
perimeter of rectangle= 2(length +breadth)
=2(5x²+2xy-13+2x²-6xy+11)
=2(5x²+2x²+2xy-6xy-13+11)
=2(7x²-4xy-2)
=14x²-8xy-4
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